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desktop/transaction: Deactivate workspace on inactive outputs

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If the output is not active, it might not have a valid geometry to
arrange for. Outputs do not gain a geometry until modeset, so if an
output is connected with a configuration present to disable it, it will
not have a geometry. If the output has a past workspace restored, this
will be attemtped arranged to fit a 0x0 rectangle, which asserts when
trying to sort out borders.

Consider the workspace activated only if the output itself is active to
get the scene nodes disabled.
This commit is contained in:
Kenny Levinsen 2024-09-06 00:36:29 +02:00 committed by Alexander Orzechowski
parent 4f9ce4675c
commit 14bff7b451
1 changed files with 1 additions and 1 deletions
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sway/desktop/transaction.c
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@ -559,7 +559,7 @@ static void arrange_output(struct sway_output *output, int width, int height) {
for (int i = 0; i < output->current.workspaces->length; i++) { for (int i = 0; i < output->current.workspaces->length; i++) {
struct sway_workspace *child = output->current.workspaces->items[i]; struct sway_workspace *child = output->current.workspaces->items[i];
bool activated = output->current.active_workspace == child; bool activated = output->current.active_workspace == child && output->wlr_output->enabled;
wlr_scene_node_reparent(&child->layers.tiling->node, output->layers.tiling); wlr_scene_node_reparent(&child->layers.tiling->node, output->layers.tiling);
wlr_scene_node_reparent(&child->layers.fullscreen->node, output->layers.fullscreen); wlr_scene_node_reparent(&child->layers.fullscreen->node, output->layers.fullscreen);